How, if at all, would the pattern seen from the right side of the film be different from the pattern seen from the left side of the film? Use your results from part a above to help justify your answer. Recall from section III of the tutorial the pattern that is observed from the left side of the film. The ray that results from the second reflection from the second (right) boundary is not shown.įor the remainder of this problem, assume that the light is incident from the left side of the film at essentially normal incidence.Ī.ğor the two rays that pass through the second boundary and into the air, what are the three smallest film thicknesses for which these rays would:ī. It shows the incident ray and several sets of rays resulting from transmission and reflection at the first (left) and second (right) boundaries. Polarized light waves are light waves in which the vibrations occur in a single plane. The cross-sectional side view in the given diagram extends the ray diagram that you drew in tutorial. It is possible to transform unpolarized light into polarized light. Light of frequency f = 4.8 × 1 0 14 H z f=4.8 \times 10^ f = 7.5 × 1 0 14 Hz is incident from the left side of a thin soap film ( n = 4 / 3 ) (n=4 / 3) ( n = 4/3 ). The process of transforming unpolarized light into polarized light is known as polarization. ![]() ![]() ![]() It is possible to transform unpolarized light into polarized light. A thin film of water ( n = 1.33 ) (n=1.33) ( n = 1.33 ) is trapped between the plates as illustrated in the diagram at right. A light wave that is vibrating in more than one plane is referred to as unpolarized light. A plate of glass ( n = 1.5 ) (n=1.5) ( n = 1.5 ) is placed over a flat plate of plastic ( n = 1.2 ) n=1.2) n = 1.2 ).
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